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cyclic shifts of one another. If is a power of , then has exactly cyclic shifts. Indeed, assume it has not, then is a power of a shorter word, and since is a power of , is even, thus one can write . Then by proposition 5, one has . It follows that does not satisfy the rhythmic oddity property, since . This implies that has exactly different cyclic shifts Corollary 2 If Proof:. One has ![]() is odd, one can write . Then . It follows which proves that is the sum of the first squares.
5 ResultsThe computation gives the following table.
Patterns actually used in Central African repertoires are indicated in the last column. There are reasons why those corresponding to the case |