- 216 -Mazzola, Guerino / Noll, Thomas / Lluis-Puebla, Emilio: Perspectives in Mathematical and Computational Music Theory 
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h(32222) = 11 h(322222) = 13 h(22223) = 11 h(222223) = 13 ... ...

Proposition 1 If w satisfies the rhythmic oddity property, then at least one of the following conditions is satisfied : (i) there exists a unique pair (u,v) with h(v) = h(u)+ 2 such that w = uv

(ii) there exists a unique pair (u,v) with h(v) = h(u)+ 2 such that w = vu

Proof: The uniqueness of the factorizations of conditions (i) and (ii) is trivial. To prove the existence of such a factorization, let u be the longest prefix of w such that h(u) < h(v) , where v is the corresponding suffix with w = uv . We denote by x the first symbol of  ' v = xv . The two possible values for x are 2 and 3 . One has  ' h(u) < h(v )+ x . Since u is maximal, one has  ' h(u)+ x >= h(v ) , but the rhythmic oddity property implies  ' h(u)+ x > h(v) , thus  ' |h(u)h(v )|< x .

  • If x = 2 , h(w) being even implies that |h(u) - h(v')| is even, thus equal to zero, and h(v) = h(u)+ 2 so that condition (i) is satisfied by the pair (u,v) and condition (ii) by the pair (v',2u) .
  • If x = 3 , h(w) being even implies that |h(u)- h(v')| is odd, thus equal to one. This gives two remaining cases.
    • If  ' h(v) = h(u)- 1 , the equality  ' h(v) = h(v )+ 3 implies that h(v) = h(u)+ 2 so that condition (i) of the property is satisfied by the pair (u,v) .
    • If h(v') = h(u)+ 1 , the factorization w = (u3)v' is such that h(u3) = h(v')+ 2 , so that condition (ii) of the property is satisfied by the pair (v',u3) .[]

Proposition 1 implies that 2h(u) +2 = h(w) = n (with n being even) so that h(u) = n/2 - 1 and h(v) = n/2 + 1 , thus expressing the »half minus one / half plus one« characterization of these patterns given in Arom (1991).

We introduce the notion of asymmetric pair that will be the key of our construction. Let u , v be words over A . We say that (u,v) is an asymmetric pairs if no pair of prefixes  ' ' (u ,v) of u and v respectively exist such that  ' ' h(v ) = h(u) +1 . For instance, (3322,32322) is an asymmetric pair, but (3322,32232) is not.

Proposition 2 A word w satisfies the rhythmic oddity property if and only if there exists an asymmetric pair (u,v) such that w = uv or w = vu with h(v) = h(u)+ 2 .

Proof: Let w = uv or w = vu with h(v) = h(u)+ 2 . The existence of a pair of prefixes (u',v') of u and v such that u = u'u'' and v = v'v'' with h(v') = h(u') +1 is equivalent to the existence of a cyclic shift v''u'u''v' of w (whatever being the


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- 216 -Mazzola, Guerino / Noll, Thomas / Lluis-Puebla, Emilio: Perspectives in Mathematical and Computational Music Theory